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a 5.00-kg mass moving at 10.0 m/s a 10.0-kg mass moving at 1.00 m/s a 15.0-kg mass moving at 10.0 m/s a 20.0-kg ass moving at 1.00 m/s Two forces, Fl and F2, are applied to a block on a frictionless, horizontal surface as shown below. = 12 N Frictionless surface Block 4. A 25-newton horizontal force northward and a 35-newton horizontal force ...

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A block of mass M is sliding down a rough inclined surface that makes an angle 𝜽 with respect to the horizontal. If the coefficient of static friction is ms and kinetic friction mk, then the acceleration of the block down the incline is equal to

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Oct 09, 2012 · So, both block move together. 37º From force diagram of combined mass (m + M), (M + m)g sin 37º = (m + M)a0 M m g sin 37º a0 m M 3 a 0 10 6m / s 2 along inclined surface. N+ma0 sin37º 5 ma0 ...

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1.00 kg block as shown below. The block, initially at rest on a frictionless horizontal connected to a spring with force constant 900 N/rn. The block moves 5.00 cm to the right surface, after is before stopping. impact a) Find the speed at which the bullet emerges from the block b) Find the mechanical energy converted into internal energy in ... A bullet of mass m and velocity vo is fired toward a block of mass 4m. The block is initially at rest on a frictionless horizontal surface. The bullet penetrates the block and emerges with a velocity of vo /3. a. Determine the final speed of the block. b. Determine the loss in kinetic energy of the bullet.

13-13. The bullet of mass m is given a velocity due to gas pressure caused by the burning of powder within the chamber of the gun. Determine the constant horizontal force developed in the coupling C, and the frictional force developed between the tires of the truck and the road during this time.The total...When an object is within the gravitational field of a planet, it has a negative amount of potential energy measured relative to infinity. where r is the distance between the centres of mass and G is the universal gravitational constant. Gravitational potential energy is measured in joules (J).

(`Light' means that we can neglect the mass of the cord and the mass of the pulley.) A force of magnitude F is applied to the mass m1 as shown, such that m1 moves to the right. The coefficient of kinetic friction between m1 and the surface is µ. Derive a formula for the acceleration of the masses.A block with mass M rests on a frictionless surface and is connected to a horizontal spring of force constant k. The other end of the spring is attached to a wall (see figure). A second block with mass m rests on top of the first block. The coefficient of static friction between the blocks is

A block with mass m 1 = 9.4 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of ? k = 0.5. A second block with a mass m 2 = 8.4 kg is connected to the first by an ideal pulley system such that the second block is hanging vertically.

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